By the work of Taylor–Wiles et al. it is known that there is a surjective morphism
from the modular curve , where
is the conductor of
.
The map sends the cusp
to the origin of
.
EXMAPLES:
sage: phi = EllipticCurve('11a1').modular_parametrization()
sage: phi
Modular parameterization from the upper half plane to Elliptic Curve defined by y^2 + y = x^3 - x^2 - 10*x - 20 over Rational Field
sage: phi(0.5+CDF(I))
(285684.320516... + 7.0...e-11*I : 1.526964169...e8 + 5.6...e-8*I : 1.00000000000000)
sage: phi.power_series(prec = 7)
(q^-2 + 2*q^-1 + 4 + 5*q + 8*q^2 + q^3 + 7*q^4 + O(q^5), -q^-3 - 3*q^-2 - 7*q^-1 - 13 - 17*q - 26*q^2 - 19*q^3 + O(q^4))
AUTHORS:
This class represents the modular parametrization of an elliptic curve
Evaluation is done by passing through the lattice representation of .
EXAMPLES:
sage: phi = EllipticCurve('11a1').modular_parametrization()
sage: phi
Modular parameterization from the upper half plane to Elliptic Curve defined by y^2 + y = x^3 - x^2 - 10*x - 20 over Rational Field
Returns the curve associated to this modular parametrization.
EXAMPLES:
sage: E = EllipticCurve('15a')
sage: phi = E.modular_parametrization()
sage: phi.curve() is E
True
Evaluate self at a point where
is given by
a representative in the upper half plane, returning a point in
the complex numbers. All computations done with prec bits
of precision. If prec is not given, use the precision of
.
Use self(z) to compute the image of z on the Weierstrass equation
of the curve.
EXAMPLES:
sage: E = EllipticCurve('37a'); phi = E.modular_parametrization()
sage: tau = (sqrt(7)*I - 17)/74
sage: z = phi.map_to_complex_numbers(tau); z
0.929592715285395 - 1.22569469099340*I
sage: E.elliptic_exponential(z)
(...e-16 - ...e-16*I : ...e-16 + ...e-16*I : 1.00000000000000)
sage: phi(tau)
(...e-16 - ...e-16*I : ...e-16 + ...e-16*I : 1.00000000000000)
Computes and returns the power series of this modular parametrization.
The curve must be a a minimal model. The prec parameter determines the number of significant terms. This means that X will be given up to O(q^(prec-2)) and Y will be given up to O(q^(prec-3)).
OUTPUT: A list of two Laurent series [X(x),Y(x)] of degrees -2, -3
respectively, which satisfy the equation of the elliptic curve.
There are modular functions on where
is the
conductor.
The series should satisfy the differential equation
where is self.curve().q_expansion().
EXAMPLES:
sage: E=EllipticCurve('389a1')
sage: phi = E.modular_parametrization()
sage: X,Y = phi.power_series(prec = 10)
sage: X
q^-2 + 2*q^-1 + 4 + 7*q + 13*q^2 + 18*q^3 + 31*q^4 + 49*q^5 + 74*q^6 + 111*q^7 + O(q^8)
sage: Y
-q^-3 - 3*q^-2 - 8*q^-1 - 17 - 33*q - 61*q^2 - 110*q^3 - 186*q^4 - 320*q^5 - 528*q^6 + O(q^7)
sage: X,Y = phi.power_series()
sage: X
q^-2 + 2*q^-1 + 4 + 7*q + 13*q^2 + 18*q^3 + 31*q^4 + 49*q^5 + 74*q^6 + 111*q^7 + 173*q^8 + 251*q^9 + 379*q^10 + 560*q^11 + 824*q^12 + 1199*q^13 + 1773*q^14 + 2548*q^15 + 3722*q^16 + 5374*q^17 + O(q^18)
sage: Y
-q^-3 - 3*q^-2 - 8*q^-1 - 17 - 33*q - 61*q^2 - 110*q^3 - 186*q^4 - 320*q^5 - 528*q^6 - 861*q^7 - 1383*q^8 - 2218*q^9 - 3472*q^10 - 5451*q^11 - 8447*q^12 - 13020*q^13 - 19923*q^14 - 30403*q^15 - 46003*q^16 + O(q^17)
The following should give 0, but only approximately:
sage: q = X.parent().gen()
sage: E.defining_polynomial()(X,Y,1) + O(q^11) == 0
True
Note that below we have to change variable from x to q:
sage: a1,_,a3,_,_=E.a_invariants()
sage: f=E.q_expansion(17)
sage: q=f.parent().gen()
sage: f/q == (X.derivative()/(2*Y+a1*X+a3))
True